hewhoknowsall
Warlord
- Joined
- Nov 30, 2009
- Messages
- 294
(note: I've also posted this proof, which I did NOT copy, on other forums, so that may be why you may see similar proof on other forums on the internet)
WARNING: nerd content, although given that this is a Civilization Fanatic forum that isn't that uncommon, right?
The high end weapon yield for a photon torpedo from the Enterprise is 64 megatons if they somehow react with 100% efficiency (which is an impossibility based on modern Science). Since the bast is omnidirectional half of it would be going in the opposite direction of the hull, so the actual upper limit in terms of the damage in which it can do is about 32 megatons.
The lower limit for the durability of the shields of a star destroyer (from Star Wars) is about 1.4E19 joules (actually, this is a very low end estimate). Converted to tons of tnt it's about 3.34 * 10^15 tons of tnt.
3.34 * 10^15 divided by 3200000 (aka 32 megatons) 1043750000.
Basically, the Enterprise would have to launch 1043750000 photon torpedos to get past the shields of a star destroyer, even when we are using high end estimates for the Enterprise and low end estimates for a star destroyer.
That's likely more photon torpedos than the Federation even has in its arsenal.
STAR TREK JUST GOT PWNED (no disrespect to Star Trek; it's a great show)
WARNING: nerd content, although given that this is a Civilization Fanatic forum that isn't that uncommon, right?
The high end weapon yield for a photon torpedo from the Enterprise is 64 megatons if they somehow react with 100% efficiency (which is an impossibility based on modern Science). Since the bast is omnidirectional half of it would be going in the opposite direction of the hull, so the actual upper limit in terms of the damage in which it can do is about 32 megatons.
The lower limit for the durability of the shields of a star destroyer (from Star Wars) is about 1.4E19 joules (actually, this is a very low end estimate). Converted to tons of tnt it's about 3.34 * 10^15 tons of tnt.
3.34 * 10^15 divided by 3200000 (aka 32 megatons) 1043750000.
Basically, the Enterprise would have to launch 1043750000 photon torpedos to get past the shields of a star destroyer, even when we are using high end estimates for the Enterprise and low end estimates for a star destroyer.
That's likely more photon torpedos than the Federation even has in its arsenal.
STAR TREK JUST GOT PWNED (no disrespect to Star Trek; it's a great show)