After thinking about it some more I am now 100% certain that Tak is town. I also agree with the analysis linking me and Tak. Here are my reasons: Tak voted for Csargo last round when Tak could have voted to kill me instead, but is now voting to kill me this round, what that tells me is Tak was guessing that Csargo and I are both wolves and wants to kill us both. That means Tak is town. There is no way a wolf would vote to kill two wolves consecutively. If Tak and I were both wolves it would make sense to save me over Csargo, if I was a PR wolf, but that theory goes out the window with Tak voting to lynch me this round. If I was a PR wolf, worth sacrificing Csargo D1 to save, Tak wouldn't then turn around and immediately lynch me on D2. So either I am a wolf and Tak is not, or neither Tak nor I are wolves. There is no way Tak can be a wolf. If Tak was a wolf killing Csargo D1 instead of me only made sense if me and Csargo were both wolves. If Tak was a wolf and I was town then obviously Tak would have killed me, so it made sense D1 to think all three of us were wolves. But now Tak is voting to kill me so it no longer makes sense to think Tak is a wolf. Tak is town and guessing that I am a wolf. Now since I know I am town, I know for certain that Tak would have voted to lynch me instead of Csargo D1 if Tak was a wolf, but there was no way for the rest of you to know that. But now with Tak opening up the day by starting a wagon on me, it should be clear to everyone that Tak can't be a wolf. Anyone still calling for Tak to by lynched has to be a suspect wolf at this point. Here is what I suggest. Lynch me instead of Tak. That will prove I am town and clear Tak once and for all. At least then we only lose 1 town instead of two. My worry is that you let the wolves convince you to lynch Tak, which will not exonerate me, even after Tak is reveled to be town, then you will lynch me because reasons, which means we lose two town instead of one. If you are hell bent on killing both of us, let it be me first, because at least then you will only make 1 mistake not two.