Originally posted by Evincar
Hey Mike, what you say is equivalent as dividing the 25 % chances of getting a tech among the remaining posibilities proporcionally to their former chances. For example:
If you have 25 % tech 50% deserted, and 25% gold, and tech is not available, the new chances are 66% deserted, 33% gold.
Maths are nice
Yes, suppose that there is a baseball game. For simplicity, I will eliminate balks and the pitcher hitting the batter with a pitch.
The batter has 3 balls and 2 strikes. This pitcher and batter are extremely consistent (the pitcher never gets tired) and the probabilities are:
strike: 30%
ball: 20%
foul ball: 50%
And of course, if the result is a foul ball, they do it again. If the result is a ball, the batter walks, and if a strike, the batter is out. In this example, a foul ball would be like an "impossible" goody hut result like barbs when you are expansionist.
The probability of an eventual strike are:
.3+(.3*.5)+(.3*.25)+(.3*.125)... which is .3*2=.6
An eventual ball: .2+(.2*.5)+(.2*.25)... = .4
In this case, a strike has 60% of the possible outcomes (30% is 60% of 50%).
So whatever a given outcome's share of the
possible outcomes on one trial, that outcome should get that share of 100%.