Riddles II

[Bose]

As i reread G-Man's answer i see that he is cactually completely correct... I thought he was saying that his answer was incorrect, as it says he was older, as he was the older twin...

OK, lets go again...

A man went to a party and drank some of the punch. He then left early. Everyone else at the party who drank the punch subsequently died of poisoning. Why did the man not die?

 

[Perfection]

ICE

 

[Bose]

Going to elaborate, or are you just listing nouns?

 

[Turner]

Nah, perf's got it. The poison was in the ice, and it melted into the punch, poisoning the rest. Since he left early, the ice hadn't melted enough to give him much, if any, poison.

Hey, I guess I'm just Perf's slave. . .

 

[Bose]

Ha ha...

Last one then i'm goin home:

A mother had two daughters who happened to be born within the same hour of the same day, in the same year. The thing is, they were not twins. How the hell does this happen?

 

[Turner]

They had another 'twin', and were really triplets.

 

[Bose]

Bugger it... I couldn't get that one.

Have a good weekend gentlemen...

 

[G-Man]

Originally posted by Bose
As i reread G-Man's answer i see that he is cactually completely correct... I thought he was saying that his answer was incorrect, as it says he was older, as he was the older twin..

I don't think I got it right... According to my solution the birthday two days later was of the younger brother, as he was born a few minutes after Kerry...

 

[Bose]

Nah, you were right. She was born just before midnight on Feb 28th, and he was born early March 1. The year in question was a leap year, so there was two days between their b'days...

Here's another:

I pass by a window, and peer in. I see a group of people inside. I conclude that there is (approximately) a 50% chance that two of those people share a birthday. How many people are in the room?

 

[KingWilly]

Is the window in the maternity ward of a hosptal, with all the newborn babies?

 

[G-Man]

Originally posted by Bose
Nah, you were right. She was born just before midnight on Feb 28th, and he was born early March 1. The year in question was a leap year, so there was two days between their b'days...

Here's another:

I pass by a window, and peer in. I see a group of people inside. I conclude that there is (approximately) a 50% chance that two of those people share a birthday. How many people are in the room?

- That would make her older than her brother, while you said in your riddle that he's the older one.

- How about 183? (just a guess...)

 

[Bose]

Its the other way around then...

 

[Beserker]

How about 365 people , guessing, or 381?

 

[mayakovsky]

The year in question was a leap year, so there was two days between their b'days...

Do I get half credit, because I said leap year? Pleeeeeeeaaaase. I will now hold my breath until you give me half credit. Starting now.

 

[G-Man]

Originally posted by mayakovsky
Do I get half credit, because I said leap year? Pleeeeeeeaaaase. I will now hold my breath until you give me half credit. Starting now.

The credit isn't his, it's mine. And I'll give you a quorter.

 

[mayakovsky]

The credit isn't his, it's mine. And I'll give you a quorter

AHHHHHHHHHHHHHHHHHHHH! Thanks, I was about to pass out. I know the credit was yours! Here is what I said:

Does it have something to do with leap year? Mix that in with G Man's answer.

So, really a quarter is probably too much. But, I'll take it!

 

[Bose]

That's the longest bow i've seen drawn for a while mayakovsky...

 

[Mariusz]

Originally posted by Bose
I pass by a window, and peer in. I see a group of people inside. I conclude that there is (approximately) a 50% chance that two of those people share a birthday. How many people are in the room?

It might be a shock for the ones who already guessed, but the answer is 23.

Explaination:

First let's count probability that among these 23 people there are no people born on the same day:

The first person can have birthday on any day, the second on any of 364 remaining, the third on any of 363, and so on...

If we substract the result from 1, we'll get probability of at least two people among 23 having birthday on the same day:
1-0,4927 = 0,5073

For 22 probabilty is less than 50%.

I hope I didn't mess up anything.

 

[Bose]

Perfect Mariusz, the explaination i was about to post was much cloudier than that...

 

[mayakovsky]

I hope this wasn't already used. I'm too lazy to check.


If you were to spell out numbers, how far would you have to go until you would find the letter "A"?