So instead of one 4 sided dice we instead use 3 two sided dice, each dice having a side 0 and 1, which is 50% chance of that strike occuring. If you roll all 3 dice then the odds of getting a total of 0, 1, 2, or 3 between them is still 25% if I am not mistaken.
I think you are mistaken, but you ended up with the right answer anyhow.
Your possible equally likely outcomes are:
0-0-0 = 0
0-0-1 = 1
0-1-0 = 1
0-1-1 = 2
1-0-0 = 1
1-0-1 = 2
1-1-0 = 2
1-1-1 = 3
So that under this scenario your odds of getting 0 FS would be 1/8, your odds of getting 1 FS would be 3/8, your odds of getting 2 FS would be 3/8, and your odds of getting 3 FS would be 1/8.
Now if we average them... (1*0 + 3*1 + 3*2 + 1*3)/8 = 1.5 FS on average if you have 3 FSC... and 1.5 first strikes (on average) out of 3 FSC means that on average you will get only 50% of the first strikes as you have FSC's.
But you will never get 1.5 FS! You are equally likely to get 1 or 2 FS's, and much less likely to get 0 or 3 FS's. This is, intuitively how it should work in the game. But according to the OP it does not.
If you use a 4-sided dice the AVERAGE is still 50% of the number of FSC's, but then 0 FSc is as likely as 1 FSc is as likley as 2 FSc is as likely as 3 FSc. As I understand it from the original poster, this is how it works. Nice to know... but not critical for playing the game.