# of civs vs tech cost
- Thread starter Delphi456
- Start date
The monopoly price of a tech will remain unchanged. The cost for each additional researcher will be reduced.
For example, suppose there are 3 remaining AI, and the monopoly price of a tech is 1000 beakers. Once one of the (known) AI has the tech, the price for you to research it will be 857 beakers.
If there are 2 remaining AI, then the monopoly price is still 1000 beakers, but once one of the (known) AI has the tech, then the price for you to research it will be 810 beakers.
For example, suppose there are 3 remaining AI, and the monopoly price of a tech is 1000 beakers. Once one of the (known) AI has the tech, the price for you to research it will be 857 beakers.
If there are 2 remaining AI, then the monopoly price is still 1000 beakers, but once one of the (known) AI has the tech, then the price for you to research it will be 810 beakers.
Lord Emsworth
Emperor
No. The number of remaing civs in the game affects only the price of already researched techs. Or more accurately, the number of civs still in the game, affects only the research cost of those techs that some civs that you have contact with already have.
Assuming you are researching, unknown, unresearched techs, then it is completely irrelevant how many civs still remain in the game.
That is at least how I understand this formula*:
http://forums.civfanatics.com/showthread.php?t=29485
The only place where CL (the number of remaining civs) shows up in the formula is the term N/[CL*1.75]. But suppose you don't know anybody who has that tech, i.e. N = 0, then the whole term will always equal 0 regardless of what you plug in for CL. For example:
0/1*1.75 = 0
0/10*1.75 = 0
0/1000000000000*1.75 = 0
* It says that it is the formula for Vanilla 1.29f, but I doubt that it is different in C3C. Anybody know?
ETA: X-post with Chamnix
Assuming you are researching, unknown, unresearched techs, then it is completely irrelevant how many civs still remain in the game.
That is at least how I understand this formula*:
http://forums.civfanatics.com/showthread.php?t=29485
Research Cost = [MM * [10*COST * (1 - N/[CL*1.75])]/(CF * 10)] - Research done so far
[...]
N = number of civs on the diplomacy screen that have discovered the tech.
CL = number of civs left in the game
[...]
N = number of civs on the diplomacy screen that have discovered the tech.
CL = number of civs left in the game
The only place where CL (the number of remaining civs) shows up in the formula is the term N/[CL*1.75]. But suppose you don't know anybody who has that tech, i.e. N = 0, then the whole term will always equal 0 regardless of what you plug in for CL. For example:
0/1*1.75 = 0
0/10*1.75 = 0
0/1000000000000*1.75 = 0
* It says that it is the formula for Vanilla 1.29f, but I doubt that it is different in C3C. Anybody know?
ETA: X-post with Chamnix
It is the same in C3. PTW and C3C. You can verify what Lord Emsworth says with either a quick Excel or some of the tech calc around. If you change the number of civs for a new tech, it has no effect. You can see it in CA as well and see the impact when others learn a tech.
