[and @ what col said]Mise said:It's probabilistic; if you have 10,000,000,000 particles, after one half life there will be 5,000,000,000 particles, on average. It won't be exact, but with so many particles, a variation of 2 or 3 is nothing. But with only 10 particles, half of that is 5, but with a variation of 2 or 3 particles that could be 8 or 2 remaining. So it doesn't exactly halve it; it is, at the end of the day, a probability.
I did some basic experiments at uni this year with radioactivity, and the probabilistic nature makes it very interesting!
But since, as has been said, we are generally dealing with between ~10^20 and 10^26 particles, a small variation is nothing.
Is it probabilistic specifically in that each atom has a 50% chance of undergoing radioactive decay in one half life?
That wouldn't seem right, because if that's the case I'd think the variation for 10^26 particles would be much more than a dozen or so, enough to be significant. (Or is that not true?) So if it's not the case, then just how does it work exactly, with regards to one particular atom?