More like yield (Turn T) = yield (Turn 1) / (1.02^T)
So turn 50 you divided by 2.7 approximately.
The curve looks reasonable until about Turn 324. At that point the discount stops being high enough, and the raw yields aren't even high enough (not even counting any snowball bonus).
To clarify, if I assume a 375 turn game. On Turn 324, the discount yields 1 science = 611.5833 SPT, multiplied by the remaining turns (51) = 31190.75. On Turn 325 its the same total. On 326, its 636 SPT, which would give you a total of
31178.27.
So this means under no circumstances would I take the 636 SPT deal on Turn 326, it is unequivocally worse than the deal of Turn 324.....again not even account for the fact that science earlier has other snowball effects. So the discount needs to be stronger here.
We may need a second function for the last 50 turns of so, the payoff requirements climb so quickly at this point that you really get a steep curve. I took the last 50 turns, and made the assumption of no snowball bonuses. Aka, what did the SPT numbers need to be just to maintain the 31190.75 number with ever shortening time to gather the science. I then calculated what the discount rate would need to be to get at that number. The curve is shown at the bottom (I ignored the data for Turn 374 as its to the moon at that point). So the discount goes from .02 to about .02 to .026 over those 50 turns. This would be the absolute minimum discount at those later turns to have viability.
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