I guess you're right; Kelvin wouldn't really work either.vonork said:Kelvin = Celsius + 273
so no real difference, I belive his point would be the difference in the structure in the air.
So would averaging work out if you use the speed of the molecules (I'm sure there's a temperature scale that does this in one way or another?). If not, why not? The difference in the structure in the air? What do you mean about that?