
http://mathworld.wolfram.com/HadamardMatrix.html
I was reading on this, and noticed that by definition those matrices must always have fewer white cells than black cells (namely for number of rows n, white cells will be n(n-1) and black cells will be n(n+1).
But if n=2 (ie the matrix has 8 rows, as in the image above) couldn't you just leave the very first top row with all white cells? Apparently this doesn't count, and i wanted to ask why.

I don't doubt the answer is simple, but if you can help it would save time for me. Moreover the actual conjecture (that Hadamard matrices/anallagmatic pavements only exist for n being 1, 2 or a multiple of 4) can be discussed
