Like I said, the earth is round and has its gravitational pull of light seen when the sun or moon are at its "sun set", "sun rise", "moon set" and "moon rise". It's kind of like an eclipse where light can still be seen around the moon when positioned in front of the sun.
The questions-not-worth-their-own-thread question thread VI
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Like I said, the earth is round and has its gravitational pull of light seen when the sun or moon are at its "sun set", "sun rise", "moon set" and "moon rise". It's kind of like an eclipse where light can still be seen around the moon when positioned in front of the sun.
Well, if you get the chance... go to the moon look at "earth set" or "earth rise" and compare it to an earth position directly above the moon.
No, it will never produce a noticeable bending.
I just did some quick calculations for you (treating light as a classical particle, assuming a gravitational acceleration of 9,81 (it's actually less, because the light is further away from earth)), of light passing over the earth. The earth's gravitational pull will lower the light beam 0,0088 m (8,8 mm) over the whole time the light is passing the earth (12000 km). In your example, this distance would be even shorter, further reducing the effect on the lightbeam.
Now, if we take this deflection of 8,8 mm on a distance of 12000 km, that means the angle of deflection is roughly 4*10^-8 degrees, in other words, totally unnoticeable. And this was a best case scenario.
edit: For reference, the angle under which we see the moon is 31/60 degree, that is about 12 million times as much as the deflection due to the earth's gravitational pull could ever dream to be.
I just did some quick calculations for you (treating light as a classical particle, assuming a gravitational acceleration of 9,81 (it's actually less, because the light is further away from earth)), of light passing over the earth. The earth's gravitational pull will lower the light beam 0,0088 m (8,8 mm) over the whole time the light is passing the earth (12000 km). In your example, this distance would be even shorter, further reducing the effect on the lightbeam.
Now, if we take this deflection of 8,8 mm on a distance of 12000 km, that means the angle of deflection is roughly 4*10^-8 degrees, in other words, totally unnoticeable. And this was a best case scenario.
edit: For reference, the angle under which we see the moon is 31/60 degree, that is about 12 million times as much as the deflection due to the earth's gravitational pull could ever dream to be.
SS-18 ICBM
Oscillator
Has anyone ever encountered a physics question where they had to determine if any injury or harm occurred to a person (e.g. calculating the g forces on a person and determining if the net force is harmful)?
Mowque
Hypermodernist
Yeah but they are tricky since it is all dependent of variables that are just about impossible to judge....Unless you have an outrageous amount of force.
SS-18 ICBM
Oscillator
It doesn't have to be precise, you could be given a value that would be harmful and then you just compare your calculated values to the given value.
There's going to be a big solar eclipse taking place on July 22nd. I suggest you observe the pictures tahken that day closely. Light bends around a massive object like our moon which is why we can see the sun's corona. The earth's gravity somehow affects the light of the sun or moon in a way that reaches our eyes.
It's like a UFO that makes these impossible turns and maneuveurs. They distort light and gravity in a way that makes it look like they are breaking the laws of physics.
Mowque
Hypermodernist
Slow down there, cowboy. Your saying UFO's are alien ships that are messing with gravity? And we don't detect the MASSIVE gravitational pressure that would cause?
PlutonianEmpire
King of the Plutonian Empire
Can anyone ELSE with better scientific knowledge answer my question?
(I saw you in that "fate of the earth" thread. Your science is flawed.)
There is no massive gravitational pressure per se, supposedly alien ships are in some plasma bubble that distorts earth's gravity as well as light.
Can anyone ELSE with better scientific knowledge answer my question?
(I saw you in that "fate of the earth" thread. Your science is flawed.)
Thank you for stating my science is flawed. It's good to know that my knowledge on the "fate of the earth" is appreciated.
Mowque
Hypermodernist
And that is more likely then people just seeing everyday objects? But sorry, that is off-topic. On topic, yes the Sun bends light...Einstein used it to prove his theory, and someone taking a picture during an eclipse was the coup de grace if I remember. But you can't see it with the naked eye under most circumstances, like sunrises or sunsets.
The reason why the sun or moon seems larger at its rise or set may be the line of sight of the sun/moon and the amount of earth's gravity in between. The light from the sun/moon would have to pass through a longer and larger amount of earth's gravity because of the angle of the person, the earth and the sun/moon. The sun/moon directly above will pass very little of earth's gravity because of its angle perpendicular to the earth.
the moons changing size is an optical illusion. all measurements show it to be the same size the whole time, and theoretically it should look smaller due to refraction in the atmosphere, though not by a noticable amount.
a link for reinforcement:http://science.nasa.gov/headlines/y2008/16jun_moonillusion.htm
and btw, we can see the corona in an eclipse because the sun appears bigger than the moon. gravitational bending of light only really reachs noticable effects with really big objects, like black holes and stars
a link for reinforcement:http://science.nasa.gov/headlines/y2008/16jun_moonillusion.htm
and btw, we can see the corona in an eclipse because the sun appears bigger than the moon. gravitational bending of light only really reachs noticable effects with really big objects, like black holes and stars
There is a mathematical equation that differentiates the distance between the moon and the earth. Actual or real distance and perceived distance taking into account the gravitational pull of the earth by measuring its curvature are the two measurements. The amount of curvature is the multiplier to actual/real distance.
Huayna Capac357
Deity
When did the US start celebrating Independence on July 4th instead of July 2nd?
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