Thank you yet again... but now i think there is an error in what you presented (unless my own view is heavily erroneus...)
It is.
let me explain:
In your image you placed the actual ellipse above the basis of the cone (which basis is not even shown), with the ellipse being a non-tilted one since the cone itself is tilted now.
Yes, which was my point. If paint let me rotate the image by an angle that's not a multiple of 90 degrees, I'd have done that so that it did conform to the convention of upright cone and tilted ellipse. Just turn your head so it looks that way. (p.s. there is no such thing as a 'tilted'/'non-tilted' ellipse).
By doing this you reversed the positions of the ellipse and the basis in regards to how the axis of the cone is related to the focus points. This meant that the axis of the cone in your example has been moved to the side, which seems also obvious from the fact that you have the axis of the cone going through exactly the point where the minor and major diameters of the ellipse meet,
Just a fluke, I tried to bisect the apex of the cone by eyeball, and that's where the line ended. The cone wasn't very accurate in the first place. It's just a paint diagram to illustrate what I'm talking about. You can not do geometric proofs just by looking at a not particularly accurate diagram.
rendering your ellipse a circle by definition, which cannot be true if the premise you based your image upon was also true.
OK, now you're really confusing me. You're saying that if the axis of a cone passes through the centre of an ellipse, that ellipse must be a circle? Why?
Is that because you're also saying that the axis of a cone must pass through the focus of an ellipse formed using that cone? And so if centre of ellipse = focus of ellipse, it's a circle?
Again, the fact the axis is *close* to the centre is just the way I drew it. It's an illustration, not an accurate diagram.
Let me have another go, I've taken a screenie, rotated it, pasted it, and done my best to make an accurate cone around the original, green-circled ellipse we were talking about. I've also extended the original axis we were talking about, the one that does intersect a focus. As you can see, the new axis is not parallel to the original axis. As you can see, the new axis does not intersect a focus.
to prove whether or not the conic axis of a right circular based cone is under some circumstances- as those mentioned above- including the one of the two focus points of the ellipse formed as a section of that cone.
I have done enough to convince myself of this. The
only circumstances in which one of the foci of an ellipse formed as a section of a right circular cone lies on the axis of that cone is when
both foci do, and the ellipse is a circle.
Funny, though, if that is so elementary to you, where exactly is the proof that the above is true or false?
I put it in this thread already:
my 'proof' said:
If you want to visualise why, imagine you have that top sphere in the end of your cone. Now, turn the cone upside down. The very top of the sphere will be on the conic axis, yeah? Rest your plane inside. If it sits perfectly on top of the sphere, you'll get a circle. As you start to angle the plane in any direction, the one point where it touches the sphere will move, the further you tilt it, the further down the sphere the contact point moves, and the less circular the ellipse you get from where the plane & cone meet. Does that make sense? Now, that single point where the plane touches the circle (F1 in the diagram) is actually the focus of the ellipse made by that plane. (and if you then drop a much bigger sphere in, so it rests on top of the plane, the point where that one touches (F2 in the diagram) is the other focus) So the focus won't be on the conic axis.
If there's anything there that looks obviously wrong, or isn't making sense, please tell me.
If you want a proof of why the sphere only touches the ellipse at one point, and why that point is a focus, you can find formal proofs by doing more reading on dandelin spheres.
but if the point where the conic axis cuts throught the actual 3d-environment shape of the ellipse is in some constant relation to the focus points...
No, it's not. I think it will be on the major axis, between the foci, and related to the eccentricity. The lower the eccentricity, the closer to the centre it will be. The greater the eccentricity, the closer to a focus. If the eccentricity is zero, it will actually be in the centre. (So I think you were right earlier, if the conic axis intersects both major & minor axes of the ellipse, then it is a circle). I have a feeling that distance from centre of ellipse to conic axis divided by distance from centre to focus will equal distance between foci divided by length of major axis, which equals the eccentricity. But that is just intuition, I could be very wrong. And it just looks like a curiosity, not a useful result.
This would allow one (perhaps) to calculate where the point the conic axis cuts through the 3d ellipse is placed, if he knows the position of either both of the (2d) focus points, or the one of them which is on the same "side" as the axis point in the ellipse...
Yes, if you have both foci, and the eccentricity of the ellipse, you can reconstruct a cone & plane, and so see where the conic axis would cut through the ellipse.