Somebody613
Somebody613
- Joined
- Nov 18, 2019
- Messages
- 2,838
I've seen somewhere a VERY DETAILED EXPLANATION on how C2C combat works, and it's extremely "first strike luck" based beyond anything else.
Fact is, "strength" gets recalculated after each round, and this means that a single "lucky shot" CAN twist the DIRECTION of the entire battle drastically.
To make a crude example:
Say, both units roll for "hit" each turn, and the math is "if I hit, I do damage=(me/you) of points", where "strength" is the same as "health".
So, let's pit two "3 points" units against each other for two rounds, but with different starting "hits".
Y means this unit "hit", N means it "missed".
1. 3/3 =(Y/N)> 3/2 =(Y/Y)> 2.33/0.5 =(Y/Y)> 2/0.
Unit 1 wins and keeps "2 points" intact.
2. 3/3 =(Y/Y)> 2/2 =(Y/Y)> 1/1 =(Y/N)> 1/0.
Unit 1 wins and keeps "1 point" intact.
3. 3/3 =(N/Y)> 2/3 =(Y/Y)> 0.5/2.33 =(Y.../N...)> 0.5/0.
Unit 1 wins and keeps merely "0.5 points" intact.
And it all gets determined by the FIRST "hit" more than anything else.
Fact is, "strength" gets recalculated after each round, and this means that a single "lucky shot" CAN twist the DIRECTION of the entire battle drastically.
To make a crude example:
Say, both units roll for "hit" each turn, and the math is "if I hit, I do damage=(me/you) of points", where "strength" is the same as "health".
So, let's pit two "3 points" units against each other for two rounds, but with different starting "hits".
Y means this unit "hit", N means it "missed".
1. 3/3 =(Y/N)> 3/2 =(Y/Y)> 2.33/0.5 =(Y/Y)> 2/0.
Unit 1 wins and keeps "2 points" intact.
2. 3/3 =(Y/Y)> 2/2 =(Y/Y)> 1/1 =(Y/N)> 1/0.
Unit 1 wins and keeps "1 point" intact.
3. 3/3 =(N/Y)> 2/3 =(Y/Y)> 0.5/2.33 =(Y.../N...)> 0.5/0.
Unit 1 wins and keeps merely "0.5 points" intact.
And it all gets determined by the FIRST "hit" more than anything else.