I’m not convinced that an AI will not give us fail gold if not in anarchy. But, if that is true, is there a way to bribe Peter into anarchy if ToA compketes?
Peter shares our religion and civics, so I don't think we can bribe Peter into Anarchy any time soon unless he gets Monotheism starting on T108?
It is possible to tell precisely the exact maximum amount of

Peter will offer to trade on any turn.
But the calculation is... complicated.
https://forums.civfanatics.com/threads/sgotm-18-kakumeika.504787/page-115#post-12894449
We have known Peter 27 turns.
Moscow is 6 out of 15 empire population.
Perform Counterespionage is 100

times multipliers, with the final number being 147
Spending penalty is 107% and we have a -20% cost due to trade route between Moscow and our cities.
Just have to figure out distance penalty
Floor (100*1.07) = 107 // spending penalty
Floor (107*0.80) = 85 // trade route bonus
Floor (85*x) = 147 // x is distance penalty
x = 73% distance penalty

This distance penalty can be checked for sure with the Test Game recreating Moscow's location and a world-buildered spy.
Now that we know the modifiers, we can calculate how much money Peter has stored in his bank.
Steal Treasury is 110

It cost 3

to steal every gold, or more espionage if there are negative modifiers.
Let us rip the modifiers out of 110.
Floor_each_division(110/0.8/1.73/1.07) = 73

without modifiers
73/3 = 24.3333

, hmm that doesn't seem right.
Ah, it is 25

25 * 3 = 75
Floor (75*0.8) = 60
Floor (60*1.73) = 103
Floor (103*1.07) = 110
Moscow steal gold mission will steal 25

, which is 6/15th Russia's total gold supply
25*15/6 = 62.5
Russia has 62 or 63
in its bank right now, total.
Now for the hard calculation.
How much of that money will Russia trade to us on T105?
The 1st cap is:
((AI Total Population * (Turns since you met the AI + 10) * iMaxGoldTradePercent)/100) - the gold the AI has traded to the player
We have known Peter 27 turns and his iMaxGoldTradePercent = 10 (Sitting Bull is 5, so he hoards his gold!

)
1st Cap = (15*(27+10) * 10)/100) = 55
2nd cap is:
AIs total gold - (12*defecit * Speed modifier)/100.
The actual slider percentage is irrelevant
62

- (12 * Peter 1-turn deficit ???) = 0

on T105 probably.
Whichever cap is lower limits how much Peter will offer us for gold that turn.
In addition, if we have gotten 10
from Peter in a past trade or beg, this amount is subtracted off the current offer.
When Peter is in Anarchy, his deficit = 0 so the 2nd cap becomes the total amount of gold Peter has in his bank
This causes the 1st cap to be the limiting factor based on turns we've known Peter and his population, so he will offer us a lot of

while in Anarchy.
Almost always it is the 2nd cap that limits how much gold the AI will trade.
It fluctuates based on how much gold the AI has in its bank along with the changing 1 turn deficit value.
Did
Mirrorguard collect any

from Peter in trades?
Any

we get from Peter is subtracted off of all future totals he will offer us.
I
only see us giving Peter 10

+ COL for Monarchy and us giving 45

+ Meditation to switch civics.
T102
The bribery costs 45g+Meditation. I don't add monotheism then.
Yes, we bribed Peter into Anarchy and he offered 30

in trade on T102.
The 2nd cap would have been at least 45

- 12*0 = 45

or higher since we gave him 45

to switch civics.
The 1st cap would have been the limiting factor.
We knew Peter for 24 turns on T102.
Peter's Empire population * 34 * 10 / 100 = 15 population -> 51

cap
14 population -> 47

cap
13 population -> 44

cap
Huh, all 3 numbers rounded down to the nearest 10 are higher than the 30

Peter offered.

Was he 13 or 14 empire population, and we got 10

from Peter earlier than T102?
Maybe we got 10
from Peter when we sold him Civil Service on T102 for Alphabet?
If we did get 10

from Peter for Civil Service, that would explain him only offering 30

while in Anarchy T102 and not 40

for having an empire population of 13 or 14.