Hehehe operator precedence is defined by operator associativity. This is just stuff that comes later in school. Just wait till you learn that a*b is not always b*a.
What we have here is trying to apply the associative law to a/b*c, which would be (a/b)*c=a/(b*c), analogous with (a*b)*c=a*(b*c) but there is no law which proves it is possible. So far. lol.
What we have here is trying to apply the associative law to a/b*c, which would be (a/b)*c=a/(b*c), analogous with (a*b)*c=a*(b*c) but there is no law which proves it is possible. So far. lol.
The second does not follow out of the first. And specifically in programming languages, some do it in reverse order. ...multiplication and division have the same precedence (so are evaluated from left to right).