Well, in that case I'm going with i: the square root of minus 1.
Or I imagine I will.
II rc the square root of -1 is not having to be 'i'*, although 'i' raised to the second power equals -1

*I don't recall now if 'i' in algebra is ever there as tied to a solution, if it is not at least raised to the second power. I hate so-called 'complex' numbers, and have an aversion to 'i' too

'i' only has four values, raised to any power:
i= i
i2= -1
i3= -i
i4=1
then each power returns to the first four positions, ie i5=i1, i6=i2 etc
