SS-18 ICBM
Oscillator
Can you guys suggest any good YouTube channels for science content?
The air is still polarized, if only slightly. Obviously the effect is much weaker than in condensed matter, but I see no fundamental difference. A photon in air could be called a polariton, even if its properties are very close to that of a photon in vacuum.
Imagine light travelling from A to B in a very dilute gas consisting of a noble gas. The gas can be treated as solid spheres, an atom not interacting with things outside a radius R. The gas is so dilute that the chance for a light ray to hit a sphere between A and B is significantly lower than 1. (A and B must be quite close!) We measure the time of flight between A and B. What will the speed of light be? Will some of the photons be able to travel from A to B with c, while others take longer, or will they all take the same time to make the journey?
Apparent magnitude of the sun at Pluto perihelion is -19.38, apparent magnitude at aphelion is -18.25, full moon on Earth is -12.74, sun on earth is -26.78.Pluto actually does have a thin nitogren atmosphere at times.
Yes, you could see all the stars because the sun is so small and dim at that distance. It'd be just like nighttime here, mostly. You could also probably see almost all of them except those close to the sun in the sky.
Can you guys suggest any good YouTube channels for science content?
Can you guys suggest any good YouTube channels for science content?
Can you guys suggest any good YouTube channels for science content?
Questions:
1. What would an apparent magnitude of -24.73 look like to the human eye?
2. How bout when pointing a typical video camera at said light source?
3. Any difference with anything with said light source positioned a few degrees of arc from the sun?
I know when I enter apparent magnitude values into wolfram alpha, sometimes (I dunno how often), it says what it looks like if you were x distance from a 100 watt incandescent light, but dunno how accurate that is.As near as makes no difference, the same as looking directly at the sun. There's a measurable difference between the apparent magnitude of the sun and your figure, but your eye would be so overwhelmed that you'd not personally be able to tell.
Unless you meant, if the star we were orbiting looked like -24.73, what daytime look like? I wanna say like earth viewed during a cloudless day with some mild sunglasses on.
I know when I enter apparent magnitude values into wolfram alpha, sometimes (I dunno how often), it says what it looks like if you were x distance from a 100 watt incandescent light, but dunno how accurate that is.
EDIT: What I meant was basically your first paragraph; a two-suns-in-the-sky scenario. Would my eye (or even a video camera for that matter) still be unable to tell a difference between the two, even though the second sun would technically be only about 15%-20% as luminous if our sun and said second one had an angular separation of about 6°?
Cool; thanks!It could only be accurate if apparent magnitude was defined in a unit that could be accurately converted into lux. But apparently it isn't, though you can only get approximations that way. If the star has a spectrum that closely resembles a blackbody radiation spectrum, the approximation should be very good (if you apply the right conversion factors). For an arbitrary light source, there is missing information, so the comparison could be far off.
If the two stars are close together you could probably tell which one is which by determining which one hurts your eyes more. I am not sure you could tell with a quick glance, as both would be saturating your eyes.
If you were looking at one of them, I don't think you would be able to tell which one it was (baring any obvious differences in color or size, of course). Human vision works on a logarithmic scale, so a fivefold increase does not make a large difference and it gets worse when the eyes are close to saturation (It is an interesting experiment to try to tell the power of a laser by looking at the brightness of the spot it makes).
Video cameras work on a linear scale, so in principle you have an easier time distinguishing them. However the stars would have to be in the range of the camera and not just saturate the pixels. That would not be the case with standard settings, so the question would be how far the settings of the camera could be adjusted beyond the standard settings (That is if the chip is not damaged by the light). If you had a set of neutral density filters, you could put filters on the camera until the light was in the range of the sensor and then you could easily tell the difference. This would also be safe for the camera. If the stars had the same spectrum, the filters would not have to be strictly neutral density, so you could use makeshift filters by holding sheets of paper in front of the lens, for example.