What makes the mathematicians so positive they are absolutely correct about this 0.999=1 stuff?
The fact that it can be proved. It follows from the definition of the symbols.
It's like the fact that red is a colour. That's part of the definition of the word "colour", whatever that may be.
You probably know that physics differs from maths in relying on observation. Maths on the other hand relies on the definitions and deduction. Surely it's possible that all the mathematicians have been mistaken. If you entertain that possibility though, you should also think, for example, if you've just learnt the English language the wrong way, and what you actually said above means "I wanna ride hippopotamus to work". It's possible, but unless given any reason to think so, it's vain to entertain the idea that it would be true.
As for proof, here it is recapped:
Check the definition of the real numbers here. Any set that satisfies the field-, order- and completeness-axioms is the real numbers.
The decimal numbers aren't defined as an axiom, but here's the definition that any mathematician would use, and that is used in any book that bothers (mutatis mutandis):
A) A decimal number with integer part 0.
0.p1p2p3p4p5...
is the sum:
p1/10+p2/100+p3/1000+p4/10000+p5/1000000+...
B) All the rest in an obvious way from that, for example 4.123123... = 4 + 0.123123...
For that definition you need to know what is an infinite sum (a.k.a. series). That is the limit of the finite partial sums:
\sum_{k=1}^{\infty} a_k := lim_{n\to\infty} \sum_{k=1}^n a_k
The limit of a sequence (an ) is defined to be the real number a for which holds:
for every e>0 there is a ne such that |an - a| < e whenever n>ne,
if such number a exists.
Now, to show that 0.9999... =1 it is sufficient to show that 1 is the limit of the partial sums. Choose an e > 0 and n0 in N such that 10^{-n0} < e. Then for the n:th partial sum S_n it is:
|S_n -1| = 10^{-n} < 10^{n0} < e whenever n>n0.
Since for every positive e there exists such n0, this proves that 1 is the limit of the partial sums (this I say only because there are people in the thread who don't understand the logic in epsilon proofs).
There.